Question

construct a rhombus with side 6 cm and one diagonal is 8 cm measure the other diagonal​

Answer 1

6 to 10 cm the other diagonal

Answer 2

Answer:

$4\sqrt{5}$

Step-by-step explanation:

Diagonals of a rhombus are perpendicular and bisect each other

therefore use pythagoras theorem

i.e  $6^{2} =(8/2)^{2} + (d/2)^{2}$

or use the theorem   $d_{1 } ^{2} + d_{2} ^{2} = 4a^{2}$   where  $d_{1},d_{2}$  are the diagonals and a is the length of a side.