Math, asked by shivkanti65, 1 year ago

construct a right angle triangle in which base if two times of the perpendicular now construct a triangle similar to it with a base 1.5 times of the original triangle

Answers

Answered by amitnrw
1

Constructed a right angle triangle in which base is two times of the perpendicular

Step-by-step explanation:

Step 1 : Draw a line AB   as Base

Step 2 : Draw a right angle at B on AB using protector/Setsquare

Step 3 : Using compass Taking width slightly less than AB,  Draw arc taking B as center on both sides of AB

Step 4 : keeping same width of  compass T  Draw arc taking A as center on both sides such that it intersects arc drawn in step 3 at X & Y

Step 5 : join XY intersecting AB at M

Step 6 : Taking compass width = BM , from B take length on Angle in drawn in step 2 and Label it C

Step 7 : join AC

Constructed a right angle triangle in which base is two times of the perpendicular

to have Base 1.5 = 3/2 time of original Base

Step 1 : taking length A'P  = AB and extend  it till  AQ

Step 2 : Draw an acute angle at A'

Step 3 : Take three point consecytively at equal distance on  angle drawn in step 2

Step 4 : join 2nd point with Q  

Step 5 : Draw a line parallel to line dawn in step 4 such that it passes through 3rd point & intersect A'Q at B'

A'B' = 1.5 AB

repeat Steps as in 1st triangle further

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