construct a right angle triangle in which base if two times of the perpendicular now construct a triangle similar to it with a base 1.5 times of the original triangle
Answers
Constructed a right angle triangle in which base is two times of the perpendicular
Step-by-step explanation:
Step 1 : Draw a line AB as Base
Step 2 : Draw a right angle at B on AB using protector/Setsquare
Step 3 : Using compass Taking width slightly less than AB, Draw arc taking B as center on both sides of AB
Step 4 : keeping same width of compass T Draw arc taking A as center on both sides such that it intersects arc drawn in step 3 at X & Y
Step 5 : join XY intersecting AB at M
Step 6 : Taking compass width = BM , from B take length on Angle in drawn in step 2 and Label it C
Step 7 : join AC
Constructed a right angle triangle in which base is two times of the perpendicular
to have Base 1.5 = 3/2 time of original Base
Step 1 : taking length A'P = AB and extend it till AQ
Step 2 : Draw an acute angle at A'
Step 3 : Take three point consecytively at equal distance on angle drawn in step 2
Step 4 : join 2nd point with Q
Step 5 : Draw a line parallel to line dawn in step 4 such that it passes through 3rd point & intersect A'Q at B'
A'B' = 1.5 AB
repeat Steps as in 1st triangle further
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