Question

construct a right angle triangle PRQ. where <PRQ= 90°, PR= 6cm and QR=8cm. ( HiNT- find hypotenuse PQ).​

Answer 1

Answer:

(i) Given:

PQ = 8 cm

QR = 6 cm

PR = ?

∠PQR = 90°

According to Pythagoras Theorem,

(PR)2 = (PQ)2 + (QR)2

PR2 = 82 + 62

PR2 = 64 + 36

PR2 = 100

∴ PR = √100 = 10 cm

(ii) Given :

PR = 34 cm

QR = 30 cm

PQ = ?

∠PQR = 90°

According to Pythagoras Theorem,

(PR)2 = (PQ)2 + (QR)2

(34)2 = PQ2 + (30)2

1156 = PQ2 + 900

1156 - 900 = PQ2

256 = PQ2

∴ PQ = 16 cm

hope it's helpful