Construct a right angle triangle whose hypotenuse and one side measures 10 cm and 8 cm then construct another triangle whose sides are 4/5 times the correponding sides of the triangle
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first draw the right angled triangle of hypotenuse 10cm and one side 8cm then mark arcs of same length on the line opposite to the triangle in this ques max ratio is 5 so draw 5 arcs on it and join it to the triangle then by making equal angles draw a picture ine parallel to it
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1. Draw a line segment BC = 8 cm.
2. Construct BM perpendicular BC.
3. Taking C as centre and radius as 10 cm, draw an arc that cuts the ray BM at A
4. Join CA to obtain ∆ABC.
5. Below BC, make an acute angle CBX.
6. Along BX mark 5 points B1, B2, B3, B4, B5 such that BB1 = B1B2 = B2 B3 = ......... = B4 B5.
7. Join B5C.
8. From B4, Draw B4C || B5C.
9. From C draw C’A’ CA meeting BA at point A’. Then A’BC’ is the required triangle.
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