Three circuits, each consisting of a switch 'S' and two capacitors, are initially charged, as shown in the figure. After the switch has been closed, in which circuit will the charge on the left-hand capacitor (i) increase, (ii) decrease and (iii) remains same ? Give reasons.
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When the capacitors are in parallel, the V should also be the same.
Q= CV
Thus, v= q/c
Same for each The charge on the left hand capacitor will increase in circuit 2 The charge on the left hand capacitor will decrease in circuit 3 The charge on the left hand capacitor will remain the same in circuit 1
Q= CV
Thus, v= q/c
Same for each The charge on the left hand capacitor will increase in circuit 2 The charge on the left hand capacitor will decrease in circuit 3 The charge on the left hand capacitor will remain the same in circuit 1
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