Question

construct a right -angled ∆ PQR whose Q=90°, QR= 8cm and PR= 10cm.

Answer 1

in ths right angle trainge PQ is ths perpendicular therefore,
Q=90°,base,QR=8cm,hypotenuse,PR=10cm,thus,perpendicular,PQ=6cm

Answer 2

Firstly take QR=8 Make a 90degree angle at Q Then, from R,cut an arc at Q And then join it, Name it as P,  PQR is the required triangle