Question

construct a right angled triangle whose hypotenuse is 6 cm long and one of the legs​

Answer 1

Step-by-step explanation:

To construct: A right angle triangle DEF where DF=6cm and EF=4cm

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:(a) Draw a line segment EF=4cm

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:(a) Draw a line segment EF=4cm(b) At point Q, draw EX⊥EF

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:(a) Draw a line segment EF=4cm(b) At point Q, draw EX⊥EF(c) Taking F as centre and radius 6cm, draw an arc (Hypotenuse)

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:(a) Draw a line segment EF=4cm(b) At point Q, draw EX⊥EF(c) Taking F as centre and radius 6cm, draw an arc (Hypotenuse)(d) This arc cuts the EX at point D

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:(a) Draw a line segment EF=4cm(b) At point Q, draw EX⊥EF(c) Taking F as centre and radius 6cm, draw an arc (Hypotenuse)(d) This arc cuts the EX at point D(e) Join DF

To construct: A right angle triangle DEF where DF=6cm and EF=4cmSteps of construction:(a) Draw a line segment EF=4cm(b) At point Q, draw EX⊥EF(c) Taking F as centre and radius 6cm, draw an arc (Hypotenuse)(d) This arc cuts the EX at point D(e) Join DFIt is the right angled triangle DEF