Construct a right triangle ABC in which Ab=5.8cm,BC=4.5cm and angle C=90degree
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Given,
An arm, AB = 5.8cm.
Another, BC = 4.5cm.
An angle, ∠C =90°.
To Find,
The way to construct a right triangle ΔABC.
Solution,
We can solve this problem in the following method.
Basically, the angle is a C point. So let's "BC" be the base.
So AB is the hypotenuse and BC be the height.
At first, let's draw a line segment BC = 4.5 cm.
Now draw any ∠BCD of measure 90°. Mark the center as B,and take a radius of AB = 5.8 cm.
And draw an arc that must intersect ray BD at A.
Join AB and now we have our triangle, ΔABC.
Hence, The constructed ΔABC with an arm, AB = 5.8cm, another, BC = 4.5cm, an angle, ∠C =90° is-
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