Construct a right triangle whose base is 8 cm and sum of the hypotenuse and
other side is 16 cm
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Answer:
1.Draw a line segment BC = 8 cm.
2.At B, Draw ∠CBX = 90°.
3.From ray BX, cut off BE = 16 cm.
4.Join CE .
5.Draw the perpendicular bisector of EC meeting BE at A.
6.Join AC to obtain the required ΔABC.
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Step-by-step explanation:
➡Given: In △ABC BC = 8 cm, ∠B= 90° and AB + AC = 16 cm.
Required : To construct ΔABC.
➡Steps of construction :
1.Draw a line segment BC = 8 cm.
2.At B, Draw ∠CBX = 90°.
3.From ray BX, cut off BE = 16 cm.
4.Join CE .
5.Draw the perpendicular bisector of EC
6.Join AC to obtain the required ΔABC
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