Question

construct a right triangle whose hypotenuse and one side measure 10 and 8 cm respectively then construct another triangle whose sides are 4 /5 times the corresponding side of this triangle.

Answer 1

Hope it will help you

Answer 2

$\bf\huge\boxed{\boxed{\bf\:Hello\:Mate}}}$

$\bf\huge\boxed{\boxed{\bf\huge\:Attached\:pic\:is\:created\:by\:me}}}$

1. Draw a line segment BC = 8 cm.

2. Construct BM perpendicular BC.

3. Taking C as centre and radius as 10 cm, draw an arc that cuts the ray BM at A

4. Join CA to obtain ∆ABC.

5. Below BC, make an acute angle CBX.

6. Along BX mark 5 points B1, B2, B3, B4, B5 such that BB1 = B1B2 = B2 B3 = ......... = B4 B5.

7. Join B5C.

8. From B4, Draw B4C || B5C.

9. From C draw C’A’ CA meeting BA at point A’. Then A’BC’ is the required triangle.

$\bf\huge\boxed{\boxed{\bf\huge\:Thanks}}}$