Question

Construct a shombus PQRS when its diagonal are 7.6cm and 4.4cm respectively​

Answer 1

STEP OF CONSTRUCTION

• Draw a line segment AC = 4.4 cm
• Draw perpendicular bisector of AC. Let it intersect AC at O.
• With O as centre and radius equal to half of BD (3.8cm) draw arcs on either side of AC on the perpendicular bisector. Let them intersect at B and D as shown.
• Join points A, B; points B, C; points C, D and points A, D.
• ABCD is the required rhombus.

Answer 2

Answer:

Check the above attachment