construct a square ABCD , whose each hypotenuse is of 6 cm
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hi aditya
Explanation:
Steps of construction:
1. Draw AC=6 cm.
2. Draw the perpendicular bisector of AC to intersect it at E.
3. With E as center and 3 cm as radius draw an arc to intersect the above at B and D.
4. Join AB,BC,CD, and DA.
Hence, ABCD is the required square is the above drawn figure.
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