Construct a square whose diagonal is 6cm
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Do, you wana make this construction through compass or scale
S.O.C :- ... 1) Draw a line segment AB of length 3√2Cm.
2) Take B as centre draw an arc whose one end touches the line segment AB.
3) Take a line From point B. Having length 3√2Cm.
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Answers
Answered by
2
let the side's of square be a
in right angled ∆ ABC
By Pythagoras theorem
6² = a² + a²
=>
2a² = 36
=>
a² = 18
=>
a = √(3²×2)
=>
a = √(3)² × √(2)
=>
a = 3√2cm
in right angled ∆ ABC
By Pythagoras theorem
6² = a² + a²
=>
2a² = 36
=>
a² = 18
=>
a = √(3²×2)
=>
a = √(3)² × √(2)
=>
a = 3√2cm
Attachments:
how have u concluded the side of square
Now I understand
Also tell me steps of construction
Answered by
1
Step-by-step explanation:
Draw a line ab of 6 cm
From both ends... Draw 2 rays.. About 45 degree from line ab on both sides
U get the square when rays meet
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