Construct a square with each diagonal equal to 7.5cm
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11
Answer.
Steps for Constructions:
Draw a line segment AC = 4.8 cm lengthNow draw perpendicular bisector of AC. Let it intersect AC at point O.With O as centre and radius equal to half of the length of the diagonal (2.4 cm) draw two arcs on either side of AC on the perpendicular bisector.Mark the point of intersections of the arcs and perpendicular bisectors as B and C.Join points A, B; points B, C; points C, D; points A, D. Thus ABCD is the required square with length of diagonal 4.8 cm.
Steps for Constructions:
Draw a line segment AC = 4.8 cm lengthNow draw perpendicular bisector of AC. Let it intersect AC at point O.With O as centre and radius equal to half of the length of the diagonal (2.4 cm) draw two arcs on either side of AC on the perpendicular bisector.Mark the point of intersections of the arcs and perpendicular bisectors as B and C.Join points A, B; points B, C; points C, D; points A, D. Thus ABCD is the required square with length of diagonal 4.8 cm.
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33
Answer:
Step 1: Draw a line segment AB = 7.5 cm. Step 2: Construct 90° angle at A and B. Step 3: With A as centre and radius = 7.5 cm, mark an arc which intersect the ray through A in D. Step 4: With B as centre and radius = 7.5 cm, mark an arc which intersects the ray through B in D.
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