Construct a trapezium ABCD in which AB||CD, AB=7cm,BC=5.8 cm , CD=4.1cm and angle B=70 degree
Answers
Answer:
Step 1 : Draw a rough diagram and mark the given measurements. Draw
CE
∥
DA
. Now AECD is a parallelogram. ∴ EC = 5 cm, AE = DC = 4 cm, EB = 3cm.
Step 2 : Draw a line segment AB = 7 cm.
Step 3 : Mark E on
AB
such that AE = 4 cm . [ ∵ DC = 4 cm ]
Step 4 : With B and E as centres draw two arcs of radius 5 cm and let them cut at C.
Step 5 : With B as centre and radius 6 cm draw an arc cutting
BY
at C.
Step 6 : With C and A as centres and with 4 cm and 5 cm as radii draw two arcs. Let them cut at D.
Step 7 : Join
AD
and
CD
. ABCD is the required trapezium.
Step 8 : From D draw
DF
⊥
AB
and measure the length of DF. DF = h = 4.8 cm, AB = a = 7 cm, CD = b = 4 cm.
Calculation of area:In the trapezium ABCD, a = 7 cm, b = 4 cm and h = 4.8 cm.
Area of the trapezium ABCD =
2
1
h(a+b)
=
2
1
(4.8)(7+4)
=
2
1
× 4.8 × 11
= × 2.4 × 11
=26.4 cm
2