Question

Construct a triangle ABC in which 5 points
BC=7 cm,<B= 45° and AB+AC = 13
cm*
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Answer 1

$\huge\mathcal\pink{ANSWER:-}$

R.E.F. Image.

Given,

to construct a ΔABC where 

BC=7cm,∠B=75∘ & AB+AC=13cm.

construction steps :-

(i) Draw a line segment BC = 7 cm as a base.

(ii) Now mark ∠B=75∘ and extend it till x.

(iii) Now, by taking radius 13 cm draw an arc from 'B' on the line of angle just projected.

(iv) Now mark it as 'D', & join C to D.

(v) Draw ⊥lar bisectors for DC and mark them as P & Q.

(vi) Now extend a line from 'B' to the ⊥lar bisector that cuts on C & D line.

(vii) Now mark that point as 'A'.

(viii) Thus, required ΔABC has been formed.

(ix) Now, try taking exactly 1/2 of the angle and mark an arc on B.

Conclusion :-

∴ The required ΔABC will BC = 7 cm,

∠B=45∘ & AB + AC = 13 cm is constructed.