Question

construct a triangle ABC in which a b + BC + CA is equals to 10 cm Angle B equal to 105 degree and Angle C equals to 90 degree​

Answer 1

Answer:

Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 10cm.

Step2: Draw an angle of 60° at P and an angle of 45° at Q.

Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.

Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C

Step.5: Join AB and AC. ∴ ΔABC is the required triangle

Answer 2

Answer:

bhai answer step by step chaiye ya construct karke chaiye