Construct a triangle ABC in which AB=5.8cm, BC+CA=8.4cms and B=60°.
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Step-by-step explanation:
To construct triangle ∆ABC
- Draw a line segment AB=5.8 cm
- With the help of protector/compass draw 60° angle at B.
- Extend that line up to P.
- Measure 8.4 cm and draw an arc of 8.4 cm on line BP.
- Join P to A.Draw a perpendicular bisector of line AP.
- The perpendicular bisector of AP on extension meet BP at C.
- Join C and A.
- Construction of ∆ABC has been done.
On measurements from figure you will find that AC = 5 cm
BC = 3.4 cm
AC+BC= 8.4 cm
which is required
Hope it helps you.
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