Question

construct a triangle ABC in which angle B=60 angle C=45 and AB+BC+CA 11cm​

Answer 1

Answer:

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Steps of construction:

1. Draw a line XY = AB+BC+CA = 11 cm

2. Make an angle equal to ∠B = 60° from X and ∠c = 45° from Y.

3. Bisect ∠PXY and ∠QYX. Let them intersect at A.

4. Make perpendicular bisector of AX and AY.

5. Join AB and AC.

So, ABC is the required triangle.