construct a triangle ABC in which angle b is equal to 60 degree angle C is equal to 45 degree and a b + BC + AC is equal to 11 cm
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figure is attached^^^
Step-by-step explanation:
- draw a line segment XY equal to AB + BC + AC = 11cm
- construct angle LXY = 60° and angle MYX =45°
- Bisect angle LXY and MYX respectively and let these bisectors intersect at point A.
- Now draw perpendicular bisector of AX and AY which meet XY at B and C respectively
- join AB , BC and AC
Hence, ∆ABC is constructed where AB + BC + AC = 11cm
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