Question

construct a triangle abc in which base bc 5 cm ,angle b = 30° and ab +ac = 5.2​

Answer 1

Answer:

$\huge\pink{answer}$

Given, in ∆ABC, base BC = 3 cm, ∠B = 30° and AB+ AC = 5.2 cm

Steps of construction

(i) First, draw base BC = 3 cm.

(ii) Construct∠YBC = 30° at the point B.

(iii) From ray BY, cut-off line segment BD = AB+ AC = 5.2 cm.

(iv) Join CD.

(v) Draw the perpendicular bisector of CD, which meets BY at A

(vi) Join AC. Thus, we get the required ∆ABC.

Justification Since, A lies on the perpendicular bisector of CD.

∴ AC = AD

Now, BD = 5.2 cm =>BA+ AD = 52 cm

∴ BA+ AC = 5.2 cm

Answer 2

Answer:

it's easy

Step-by-step explanation:

first draw the base 5cm helf of ruler.

now touch protecter on point be and major the 30 angle on it and dot it

no help of ruler draw an line on it

and ab+ac get 5.2 major with scale

if you gave 30 angle spot the curcutor on n it nd draw. an cross x on the top and your triengle was ready