construct a triangle ABC in which base BC is equal to 3 cm and angle b is equal to 30 degree and a b + AC is equal to 5.2 CM also justified
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Step-by-step explanation:
After constructing BC and angle B, fix point A on this line such that BA=9.
Join AC and bisect AC to intersect BA at P. Join PC.
Now PBC is the required triangle.
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HEYAA...
The below given steps will be followed to draw the required triangle.
Step I: Draw the line segment BC = 3 cm and at point B, make an angle of 30°, say ∠XBC.
Step II: Cut the line segment BD = 5.2 cm (equal to AB + AC) on ray BX.
Step III: Join DC and draw the perpendicular bisector PQ of DC.
Step IV: Let it intersect BX at point A. Join AC. ΔABC is the required triangle.
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