Question

Construct a triangle ABC in which BC = 3.8 cm, AB + CA = 6.8 cm and ∠B = 45. ​

Answer 1

Answer:

(1) Draw base of 3.8 cm name it BC

(2) Draw 45°angle

(3) Cut 6.8 cm arc on the angle

(4) Join the arc to point C

(5) Bisect the last side

do it step by step you'll get it

Answer 2

Answer:

$\underline\mathfrak\green{Steps\:\:\:of\:\:\:construction\:\::-}$

• Draw BC = 3.8 cm

• Draw $\angle$ CBX = 45°

• From ray BX, cut - off line segment BD equal to AB + AC i.e., 6.8 cm.

• Join CD.

• Draw the perpendicular bisector of CD meeting BD at A.

• Join CA to obtain the required triangle ABC.

_______________

$\underline\mathfrak{\:\:\:Justification\:\:\::-\:\:\:}$

A lies on the perpendicular bisector of CD.

$\therefore$ AC = AD

$\\ \rightarrow \: \sf \: BA+ AD = 6.8 \: cm \\ \\ \rightarrow \: \sf \: AB+AC= 6.8 \: cm$

Hence, ∆ ABC is a required triangle.