construct a triangle abc in which bc= 4.5cm angle b = 45° and ac-ab = 2.5cm
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Step-by-step explanation:
i) Draw a ray BX and cut off a line segment BC = 4.5 cm from it.
(ii) Construct ∠XBY = 450
(iii) Cut off a line segment BC = 2.5 m from BY.
(iv) Join AC.
(v) Draw perpendicular bisector of CD cutting BY at a point A.
(vi) Join AC. So, ΔABC is the required triangle.
hope it's helpful to you dear
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