Question

Construct a triangle ABC in which BC =5 cm, angle B= 75° and AB + AC=9 cm.​

Answer 1

Step-by-step explanation:

I'd:925 083 1926

pass:1111

Answer 2

Step-by-step explanation:

Steps to construction:-

Step i.Draw a line segment BC=5cm. At point B,Costruct a AngleXBC=75°

Step.ii.Cut a line segment BD=AB+AC= 9cm from the ray BX.

Step.iii.Join CD.

Step.iv Draw a perpendicular bisector PQ of CD,Which intersect BD at A.

Step.v.Join AC.

Step.vi.Then,∆ABC is the required triangle .This is because point A lies on the perpendicular Bisector of CD.

A.T.Q. AD=AC

==>BD=AB+AD=AB+AC