Construct a triangle ABC in which BC = 5 cm , ∠ C = 90◦ and AB + AC = 12 cm.
write construction step also.
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Given :- In ∆ ABC, BC=5cm,<C=90°, AB+AC=12cm.
Solution :- First - draw base of 5cm then , take a protractor and make an angle of 90° and mark as <C.
Second - use compass and draw a arc of 12cm from point C.
Third - and then draw arc from point B as well of 12cm on point A.
- THAT'S IT YOUR ∆ IS DONE.
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