Question

Construct a triangle ABC in which BC=5 cm, CA=6 cm and AB=7 cm. Construct another triangle DEF each of whose sides are 7/5 times the corresponding sides of triangle ABC.
Please this is very urgent, I would be very grateful if my ques. gets answered soon.

Answer 1

Hello friend !!

We follow these steps to construct angle ABC .

Step 1 : Draw a line BC = 6 cm .

Step 2 : Now take any radius ( Less than half of BC ) and take center " B " draw an arc that intersect our line BC at " P " , With same radius and center is " P " draw another arc that intersect our previous arc at " Q " .

Step 3 : Join BQ and extend it to D

Step 4 : Take radius = 5 cm and center " B " we draw an arcs that intersect our line BD at " A " Now we join AC , and get triangle ABC .

Now We construct another triangle with scale factor 57 , As :

Step 5 : Draw a line BT As ∠ CBTis any acute angle and draw seven equal radius arc on line BT that intersect at T1 . T2 , T3 , T4 , T5 , T6 and T7 AS :

BT1 = T1 T2 = T2 T3 = T3T4 = T4T5 = T5T6 = T6 T7

Step 6 : Join T7 to C and than draw a line from T5 as parallel to T7C that intersect our line BC at C' .

Step 7 : Draw line from C' as parallel to AC that intersect line AB at A' .

Hope it helps