Question

construct a triangle ABC in which BC=5cm,and AB+Ac=7cm​

Answer 1

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Step I: Draw a line segment BC of 7 cm. At point B, draw an angle of 75°, say ∠XBC.

Step II: Cut a line segment BD = 13 cm (that is equal to AB + AC) from the ray BX.

Step III: Join DC and make an angle DCY equal to ∠BDC.

Step IV: Let CY intersect BX at A. ΔABC is the required triangle.

Hope you understood

Answer 2

Step-by-step explanation:

construct triangle ABC in which BC=5cm and AB+AC=7cm