Question

construct a triangle ABC in which BC=5cm angle B=75° and AB+AC=9cm

Answer 1

Step-by-step explanation:

1)draw BC 5cm .

2) draw the angle 75° .

3)take 4.5 cm and join it .

Answer 2

According the question, we have to construct a triangle ABC in which BC=5cm angle B=75° and AB+AC=9cm.

In Δ ABC , BC = 5cm , AC + AB = 9cm and ∠ B = 75°.

To construct : Δ ABC

Steps of construction :

• At the beginning we will draw a ray BX and cut off a line segment BC = 5cm from it.

• At the point B we will construct ∠ XBY  =75° .

• With B as center and radius = 9cm , draw an arc at meet BY at D.

• now will join CD.

• Here we will draw the perpendicular bisector of CD, by marking arc of length more than half of CD from both points C and D on both sides of it.

• This line will be intersecting BD at  point A .

•  Now we will join AC .

         ABC is the required triangle .

Ans :- ABC is the required Δ.

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