Question

Construct a triangle ABC in which BC = 5cm, ∠B = 45° and AB + AC = 10cm.​

Answer 1

Answer:

bahut easy hai try karo aur phir pucho

Answer 2

Step-by-step explanation:

1.Draw base BC of length 5cm

2.Now, let's draw ∠B=45

∘

.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

Since AB+AC=10cm is positive.

So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC