Question

construct a triangle abc,in which bc = 6.5cm, ab+ac=10cm and angle c =60 degree

Answer 1

I draw it roughly without using any instrument but the method is correct.

HOPE IT HELPS U.

Answer 2

Construction of ∆ABC is attached.

Given:

• A ∆ ABC.
• BC=6.5 cm angle C=60°, AB+AC= 10 cm.

To find:

• Construct and justify.

Solution:

Steps of construction:

1. Draw a line segment BC of 6.5 cm with the help of pencil and scale.
2. Draw $\angle XCB=60^{\circ}$ with the help of compass /protector.
3. Mark an arc of radius 10 cm on ray CX; the point is L.
4. Join L and B.
5. Draw perpendicular bisector of LB.
6. Mark the point A, where perpendicular bisector intersects the ray CX.
7. Join A and B.
8. Construction of ∆ABC is over.

Justification:

On measurement of sides of ∆ABC.

It is clear that

AC= 4.4 cm

AB= 5.6 cm

Thus,

AB+AC= 10 cm

Hence verified.

Learn more:

1) Construct a triangle PQR in which QR = 4.6 cm, Q= 45° and PQ+PR = 8.2 cm.

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2) Construct a Triangle ABC In which BC = 3.6 cm, AB + AC = 4.8 cm and angle B = 60 Degree

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