Construct a triangle ABC in which BC = 6cm, ∠B = 75° and AB + AC = 10cm
Answers
Answered by
8
STEPS OF CONSTRUCTION :
➙Draw a ray BX and cut off a line segment BC = 6cm; from it.
➙At B; construct angle YBX = 75°
➙With B as centre and radius = 14 cm (because AB + AC = 124cm) draw an arc to meet BY at D.
Join CD.
➙Draw Perpendicular bisector PQ of CD intersecting BD at A.
➙Join AC.
➙Then ABCis the required triangle.
➙A lies on perpendicular bisector of CD.
Therefore, AC = AD
AB BD- AD
AB = BD - AC
➙AB+ AC = BD = 14cm,
Which is true as given.
Similar questions