Question

Construct a
triangle ABC in which BC = 7cm, LB=75
& AB+AC =13 cm​

Answer 1

Answer:

Steps of Construction

(i) Draw BC = 7 cm.

(ii) Construct ∠YBC = 75°.

(iii) From ray BY, cut-off line segment BD = AB + BC = 13cm.

(iv) Join CD.

(v) Draw the perpendicular bisector of CD meeting BY at A.

(vi) Join AC to obtain the required triangle ABC.

Justification

Since A lies on the perpendicular bisector of CD.

∴ AC = AD

Now BD = 13 cm

⇒ BA + AD = 13 cm

⇒ BA + BC = 13cm

Hence, △ABC is the required triangle

Answer 2

Answer:

4/6=67

68/7=89

5/6=78

=>=668