Question

Construct a triangle ABC in which BC = 8 cm, B = 60° and AB + AC = 11 cm.

Answer 1

Steps of construction:

1) Draw the base BC = 8cm

2) At the point B make an angle XBC = 60°

3) Cut a line segment BD equal to AB + AC = 11 cm from the Ray BX.

5) Join DC

6) Make an angle DCY = angle BDC.

7) Let CY intersect BX at A.

Then, ABC is the required triangle.

Hope you are satisfied.

Is it OK? Do you want me to draw it... like on a paper? Or do you have any doub ts?

Answer 2

Answer

Construction

• Draw a line BC= 8cm in staright line
• Place a protector in B and mark angle at 60° and connect tha angle to B
• where AB + AC = 11 cm from the B , draw a arc at D
• Join DC
• by the way <BDY=<DCX
• so required triangke is formed ABC