Question

Construct a triangle ABC in which BC= 8cm, B = 45° and AB-AC = 3.5 cm.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

The steps of construction to be followed:

Step 1: Draw a line segment BC = 8cm and make an angle of 45^{\circ} at point B i.e., \angle XBC.

XBC

Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.(AB-AC).

Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.

XCD 45

Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,

atep 3

Step 5: Join AC, to get the required triangle \triangle ABC.