Construct a triangle ABC in whicj BC =8cm , angle B =45° , AB-AC =3.5. from construction
Attachments:
![](https://hi-static.z-dn.net/files/df4/1f8fa7d447b804dbf7957d60334d2257.jpg)
Answers
Answered by
1
Answer:
Diagram of this question.
Step-by-step explanation:
please like and brainlist the answer.
Attachments:
![](https://hi-static.z-dn.net/files/d01/fc6062cac56421d46b4dc5c40e055278.jpg)
Answered by
6
Answer:
1.Draw base BC of length 8cm
2.Now, let's draw ∠B=45∘.Let the ray be BX
3.Open the compass to length AB−AC=3.5cm.
Since AB−AC=3.5cm is positive.
So, BD will be above line BC
From point B as center, cut an arc on ray BX.
Let the arc intersect BX at D
4.Join CD
5.Now, we will draw perpendicular bisector of CD
6.Mark point A where perpendicular bisector intersects BD
7.Join AC
Result:∴△ABC is the required triangle.
hope it helps you
Attachments:
![](https://hi-static.z-dn.net/files/d11/5c51ba4df1a681c62805aa6904c16768.jpg)
Similar questions