Question

The diagnol of rectangle √4141cm and it's area is 2020 sq cm what is perimeter of the rectangle ​

Answer 1

answer

let a, b, c, d, are sides of rectangle , e be diagonal of rectangle

given area of rectangle = ab = 2020 sq cm

by Pythagoras Therom

e^2 = a^2 + b^2

(√4141)^2 = a^2 + b^2

4141 = (a+b)^2 - 2ab

4141 = (a+b)^2 - 2(2020)

4141 + 4040 = (a+b)^2

8181 = (a+b)^2

√8181 = a+b

90.45 = a+b

45.23 = 2(a+b)

so perimeter of rectangle = 45.23 sq cm

hope this helps you