Question

Construct a triangle ABC such that B = 45 c=60 and AB+BC+CA=10 cm

Answer 1

Step-by-step explanation:

Step 1: Draw a line segment PQ ( = AB + BC + CA ) = 10cm.

Step 2: Draw an angle of 60° at P and an angle of 45° at Q.

Step 3: Bisect ∠P and ∠Q. Let the bisectors of ∠P and ∠Q intersect in A.

Step 4: Draw perpendicular bisector DE of AP which intersect PQ in B and FG of AQ which intersect PQ in C.

Step 5: Join AB and AC.

∴ ΔABC is the required triangle.

√\______Anushka❤❤