construct a triangle abc with ab=5cm, bc=6cm and ac=7cm. then construct another triangle whose sides are 3/5 times the corresponding sides of triangle abc. thumbs up please. :)
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Step 1 : Draw a line BC = 6 cm and take radius of 5 cm and center " B " draw an arc and with radius of 7 cm and center " C " draw an arc that intersect our previous arc at " A " .
Step 2 : Join AB and AC , we get triangle ABC
Now We construct another triangle with scale factor 35 , As :
Step 1 : Below BC, draw a line BX As ∠ CBX is any acute angle and draw three arcs of equal radii on line BX that intersect at X1 . X2 , X3 , X4 and X4 AS :
BX1 = X1 X2 = X2 X3 = X3 X4 = X4 X5
Step 2 : Join X5 to C and than draw a line from X3 as parallel to X5C that intersect our line BC at C' .
Step 3 : Draw line from C' as parallel to CA that intersect line AB at A'
We get triangle A'BC' whose sides are 35 of corresponding sides of triangle ABC .
Hope this information will clear your doubts about Constructions.
Step 2 : Join AB and AC , we get triangle ABC
Now We construct another triangle with scale factor 35 , As :
Step 1 : Below BC, draw a line BX As ∠ CBX is any acute angle and draw three arcs of equal radii on line BX that intersect at X1 . X2 , X3 , X4 and X4 AS :
BX1 = X1 X2 = X2 X3 = X3 X4 = X4 X5
Step 2 : Join X5 to C and than draw a line from X3 as parallel to X5C that intersect our line BC at C' .
Step 3 : Draw line from C' as parallel to CA that intersect line AB at A'
We get triangle A'BC' whose sides are 35 of corresponding sides of triangle ABC .
Hope this information will clear your doubts about Constructions.
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