Math, asked by sharwin6951, 1 year ago

construct a triangle abc with ab=5cm, bc=6cm and ac=7cm. then construct another triangle whose sides are 3/5 times the corresponding sides of triangle abc. thumbs up please. :)

Answers

Answered by Anonymous
40
Step 1 :  Draw a line BC  = 6 cm and take radius of 5 cm and center " B "  draw an arc and with radius of 7 cm and center " C "  draw an arc that intersect our previous arc at  " A "  .

Step 2 : Join AB and AC , we get triangle ABC

Now We construct another triangle with scale factor 35 , As :
              
Step 1 : Below BC,  draw a line BX  As  ∠ CBX is any acute angle and draw three arcs of equal radii on line BX that intersect at X1 . X2 , X3 , X4 and  X4 AS :

  BX1  = X1 X2 = X2 X3 = X3 X4 = X4 X5

Step 2 : Join X5 to C and than draw a line from X3  as parallel to X5C that intersect our line BC at C' .

Step 3 : Draw line from C' as parallel to CA that intersect line AB at A'

We get triangle A'BC' whose sides are 35 of corresponding sides of triangle ABC .
Hope this information will clear your doubts about Constructions.
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Answered by sumu27
15
Hope it helps you :)
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