Construct a triangle ABC with BC=3.5 cm, /_ ABC=80° and AC= 5.4 cm.
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Step-by-step explanation:
1. Construct the line segment BC of length 3.5 cm.
2. At B, construct 80° with protractor and extend a ray such that it makes an angle of 80°.
3. With center as C and radius 5.4 cm, draw an arc on the extended ray.
4. Name the point as A. ABC is the required triangle.
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Step 1: Draw a line segment BC = 8cm and make an angle of Step
Step 2: Now, cut the line segment BD = 3.5 cm on ray BX. i.e.
Step 3: Join CD and draw a perpendicular bisector of CD i.e., PQ.
Step 4: Let the perpendicular bisector of CD intersects BX at point A. Then,
Step 5: Join AC, to get the required triangle
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