Question

Construct a triangle ECD with EC = ED = 6.8 cm, CD = 5.6 cm. What special name is given to such a triangle?
Please tell fast

Answer 1

Answer:

The required triangle is drawn in the attachment.

STEPS:

• Draw a line segment CD = 5.6cm.
• Taking C as a point, draw an arc of 6.8cm.
• Similarly, Taking D as a point, draw an arc of 6.8 cm which intersects the arc draw by point C.
• Both arcs interest at a particular point E.
• Join CE and DE.
• DE = CE = 6.8cm.

→ Hence, ∆ECD is the required triangle.

→ The triangle is isosceles triangle because 2 sides of a triangle are equal and other one side is different.

Answer 2

Given :  EC=ED=6.8cm CD=5.6cm

To Find : construct  triangle ECD  

Solution:

Step 1 : Draw a line segment CD  = 5.6 cm

Step 2 : Using compass width = 6.8 cm and taking C as center draw an arc

Step 3 : keeping  compass width same and taking D as center draw an arc such that it intersects arc drawn in previous step at E

Step 4 : Join EC & ED

ΔECD is constructed

This is an Isosceles triangle  as it has 2 equal sides

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