Construct a triangle ECD with EC = ED = 6.8 cm, CD = 5.6 cm. What special name is given to such a triangle?
Please tell fast
Answers
Answer:
The required triangle is drawn in the attachment.
STEPS:
- Draw a line segment CD = 5.6cm.
- Taking C as a point, draw an arc of 6.8cm.
- Similarly, Taking D as a point, draw an arc of 6.8 cm which intersects the arc draw by point C.
- Both arcs interest at a particular point E.
- Join CE and DE.
- DE = CE = 6.8cm.
→ Hence, ∆ECD is the required triangle.
→ The triangle is isosceles triangle because 2 sides of a triangle are equal and other one side is different.
Given : EC=ED=6.8cm CD=5.6cm
To Find : construct triangle ECD
Solution:
Step 1 : Draw a line segment CD = 5.6 cm
Step 2 : Using compass width = 6.8 cm and taking C as center draw an arc
Step 3 : keeping compass width same and taking D as center draw an arc such that it intersects arc drawn in previous step at E
Step 4 : Join EC & ED
ΔECD is constructed
This is an Isosceles triangle as it has 2 equal sides
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