Question

construct a triangle in which ab = 5 cm AC = 7 cm BC = 6 cm and construct a triangle similar to triangle ABC​

Answer 1

Ello user !!!!!!!!!

Here is your answer,

========================================

Step 1 :  Draw a line BC  = 6 cm and take radius of 5 cm and center " B "  draw an arc and with radius of 7 cm and center " C "  draw an arc that intersect our previous arc at  " A "  .

Step 2 : Join AB and AC , we get triangle ABC

Now We construct another triangle with scale factor 35 , As :

             

Step 3 : Below BC,  draw a line BX  As  ∠ CBX is any acute angle and draw three arcs of equal radii on line BX that intersect at X1 . X2 , X3 , X4 and  X4 AS :

 BX1  = X1 X2 = X2 X3 = X3 X4 = X4 X5

Ste4 : Join X5 to C and than draw a line from X3  as parallel to X5C that intersect our line BC at C' .

Step 5 : Draw line from C' as parallel to CA that intersect line AB at A'

We get triangle A'BC' whose sides are 35 of corresponding sides of triangle ABC .

Hope this information will clear your doubts about Constructions

=====================================================

HOPE THIS HELPS YOUU :)

AND STAY BLESSED.