construct a triangle in which angle b=90,AB=BC,AB+AC=10.3cm
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Answer:
Hope u like my process
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Given,
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A right angled triangle,
=> Angle ABC = 90
=> AB =BC
i.e. Perpendicular = base.
=> AB+AC =10.3
AC (Hypotenuse) = 10.3 - AB
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NOW,
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By Pythagoras theorem
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=>( AC) ² = (AB) ² + (BC) ²
or, (10.3 - AB) ² = (AB) ² +(AB) ²
or, (10.3)² - 2×10.3×AB +(AB) ² = 2(AB)²
or, (AB)² + 20.6AB - 106.09 = 0
or,
Now,
AC = 10.3-AB = 10.3-4.26=6.04
And AB=BC = 4.26
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Hope this is ur required answer
Step-by-step explanation:
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