Math, asked by darkknight66, 3 days ago

Construct a triangle in which BC = 8 cm, B = 60 ∠ and AB + CA = 15 cm. Write steps of construction in brief.

Answers

Answered by p963096
0

Answer:

1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45∘.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

 Since AB−AC=3.5cm is positive.

 So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

Answered by Sraagurjit
0

Step-by-step explanation:

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Class 9

>>Maths

>>Constructions

>>Construction of Triangles

>>Construct a triangle ABC in which BC = 8

Question

Construct a triangle ABC in which BC=8cm,∠B=45∘ and AB−AC=3.5cm

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Solution

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1.Draw base BC of length 8cm

2.Now, let's draw ∠B=45∘.Let the ray be BX

3.Open the compass to length AB−AC=3.5cm.

 Since AB−AC=3.5cm is positive.

 So, BD will be above line BC

From point B as center, cut an arc on ray BX.

Let the arc intersect BX at D

4.Join CD

5.Now, we will draw perpendicular bisector of CD

6.Mark point A where perpendicular bisector intersects BD

7.Join AC

Result:∴△ABC is the required triangle.

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