Question

construct a triangle of sides 4cm 5cm and 6cm and then a triangle secular to it whoes sides are 2/3 of the corresponding sides of the first triangle
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Answer 1

Answer:

1) DrawBC=4cm

2) Cut arc of 5 cm from B and arc of 6 cm from C. Mark point of intersection as A.

3) Draw BD making an acute angle with BC. Mark 5 equal arcs on BD.

4) Join B

5

to C, draw a line B

3

C

′

parallel to B

5

C.

5) Draw a line C

′

A

′

parallel to CA.

A

′

BC

′

ia the required triangle.

solution