Question

construct a triangle of sides 4cm,5cm and 6cm.then construct a triangle similar to it,whose sides 2/3of corresponding sides of the first triangle

Answer 1

Steps of Construction:

Step I: AB = 6 cm is drawn.

Step II: With A as a centre and radius equal to 4 cm, an arc is draw.

Justification:

∠A(Common)

∠C = ∠C' and ∠B = ∠ B' (corresponding angles)

Thus ΔAB'C' ~ ΔABC by AAA similarity condition

From the figure,

AB'/AB = AA2/AA5 = 2/3

AB' =2/3 AB

AC' = 2/3 AC

Answer 2

Step-by-step explanation:

Answer

Hey Refers to this attachment