construct a triangle of sides 4cm ,5cm and 6cmand then a triangle similar to it whose side are 2by3 of corresponding sides of the first triangle
Answers
Answer:
Let's first construct △ABC with sides 4cm,5cm,6cm
Steps to draw △ABC
1. Draw base AB of side 4cm.
2. With A as centre , and 5cm as radius, draw an arc.
3. With B as centre , and 6cm as radius ,draw an arc.
4. Let C be the point where two points intersect.
5. Join AC and BC
Thus △ABC is the required triangle
Now, lets make the triangle similar to this named as △PQR whose sides are
3
2
of the corresponding sides so the sides will become
3
8
cm,
3
10
cm,4cm
Steps to draw △PQR
1. Draw base PQ of side
3
8
cm.
2. With P as centre , and
3
10
cm. as radius, draw an arc.
3. With Q as centre , and 4cm as radius ,draw an arc.
4. Let R be the point where two points intersect.
5. Join PQ and PR
Thus △PQR is the required triangle
solution
Let's first construct △ABC with sides 4cm,5cm,6cm
Steps to draw △ABC
1. Draw base AB of side 4cm.
2. With A as centre , and 5cm as radius, draw an arc.
3. With B as centre , and 6cm as radius ,draw an arc.
4. Let C be the point where two points intersect.
5. Join AC and BC
Thus △ABC is the required triangle
Now, lets make the triangle similar to this named as △PQR whose sides are 2/3 of the corresponding sides so the sides will become 8/3 cm,10/3cm,4cm
Steps to draw △PQR
1. Draw base PQ of side 8/3cm.
2. With P as centre , and 10/3cm. as radius, draw an arc.
3. With Q as centre , and 4cm as radius ,draw an arc.
4. Let R be the point where two points intersect.
5. Join PQ and PR
Thus △PQR is the required triangle