Question

Two cross roads each of width 2m , cross each other at right angle and parallel to sides through the centre of the square of side 16cm. The area of road is​

Answer 1

Answer:

0.99 hectares

Step-by-step explanation:

Here, PQ=10m and PS=300m, EH=10m and EF=700m

And KL=10m and KN=10m

Area of roads = Area of PQRS+Area of EFGH−Area of KLMN

[∵ KLMN is taken twice, which is to be subtracted]

=PS×PQ+EF×EH−KL×KN

=(300×10)+(700×10)−(10×10)

=3000+7000−100

=9,900m

2

Area of road in hectares, 1m

2

=

10000

1

hectares

∴9,900m

2

=

10000

9900

=0.99 hectares

Now, Area of park excluding cross roads = Area of park−Area of road

=(AB×AD)−9,900

=(700×300)−9,900

=2,10,000−9,900

=2,00,100 m

2

=

10000

200100

hectares=20.01 hectares

Answer 2

Answer:

450cm, 2 is the area of the triangle