Question

construct a Triangle PQR given that PQ=5.4 cm,QR=PR=4.7 cm Name triangle.​

Answer 1

Answer:

THE ANSWER IS IN THE PHOTO GRAPH SO PLEASE CO- OPERATE

FIRST STEP- DRAW  THE BASE OF 5.4CM NAMED PQ

SECOND STEP - DRAW ONE ARC FROM THE POINT  P OF 4.7CM FROM YOUR ROUNDER

THEN DRAW A SECOND ARC FROM  POINT Q NAME THE POINT WHERE THE BOTH ARCS MMET AS R

NOW YOU CAN SEE HOW IT WILL FORM

Answer 2

Diagram is drawn in Attachment for your reference.

Step-by-step explanation:

Step 1 : Mark a point anywhere take a ruler and construct a horizontal straight line measuring 5.4 cm and name the line as PQ.

Step 2: Now take a protector and measure 4.7 cm with the help of ruler, now keep the the protector at point P and cut an arc measuring 4.7 cm.

Step 3 : Now keep the protector at point Q and cut an arc measuring 4.7 cm.

Step 4 : Mark the point of intersection of 2 arc's as point R.

Step 5 : Construct a line from point P to point R and from point Q to point R.

Hence A triangle PQR is drawn in the attachment.