construct a Triangle PQR given that PQ=5.4 cm,QR=PR=4.7 cm Name triangle.
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Answer:
THE ANSWER IS IN THE PHOTO GRAPH SO PLEASE CO- OPERATE
FIRST STEP- DRAW THE BASE OF 5.4CM NAMED PQ
SECOND STEP - DRAW ONE ARC FROM THE POINT P OF 4.7CM FROM YOUR ROUNDER
THEN DRAW A SECOND ARC FROM POINT Q NAME THE POINT WHERE THE BOTH ARCS MMET AS R
NOW YOU CAN SEE HOW IT WILL FORM
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14
Diagram is drawn in Attachment for your reference.
Step-by-step explanation:
Step 1 : Mark a point anywhere take a ruler and construct a horizontal straight line measuring 5.4 cm and name the line as PQ.
Step 2: Now take a protector and measure 4.7 cm with the help of ruler, now keep the the protector at point P and cut an arc measuring 4.7 cm.
Step 3 : Now keep the protector at point Q and cut an arc measuring 4.7 cm.
Step 4 : Mark the point of intersection of 2 arc's as point R.
Step 5 : Construct a line from point P to point R and from point Q to point R.
Hence A triangle PQR is drawn in the attachment.
Attachments:
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