Question

Construct a triangle PQR in which < Q = 60ᵒ, PQ = 5 CM, and

QR = 6 CM

To construct the triangle, follow the following steps

1) Draw an angle < XQY of measure 60ᵒ

2) On ray QX draw an intersecting arc of radius 6 cm and name the point of

intersection as R

3) On ray QY draw an intersecting arc of radius 5 cm and name the point of

intersection as P

4) Join PR to obtain the required triangle PQR

5) MEASURE THE LENGTH OF SEG PR = ?​

Answer 1

Answer:

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